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cos©-sin©

Squaring this we get cos2 © — 2cos © sin © + sin2 © = 1 — 2cos © sin © = 1 — sin2 ©. From weak coupling to Av = 0 the angle © goes from 0 to 45° and the intensity of the outer lines goes from 1 to 0. The same result is obtained for line 4, the other "outer" line of the AB system.

[0 sin© cos© 0] x
0 0

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